If you send your project, we will check it. If the bond beam curtain you checked in the project you entered is the same as the entered project when you isolate it, the Nv and M values for the triangle loading and response results of the two system solutions are compatible, and as a result, the bond degree coefficient Since I can't see your project, I'm showing you the results of the analysis under fictitious load, based on the numerical values of the project, whose data I have put here (Fictive upload omega.ide10). The attached project is c=8 m and only two curtains and omega condition between them. There is a tie beam that does not provide omega 0.233 calculated by the program omega 0.233 found with fictive loading Program file: Program automatically For the fictitious loading it makes, a loading status called fictitious load is also entered in the program and the loading result is found by entering the fictitious load in the form of an inverted triangle from top to bottom, respectively 1.02 tf 0.85 tf 0.71 tf 0.57 tf 0.43 tf 0.28 tf 0.14 tf c=8 m t Nv=3.522 M1=46.123 tfm M2=46.062 tfm Omega = cx Nv / ( M1 + M2 + cx Nv) Omega = 0.233 Values found as a result of response spectrum calculation: c=8 m Nv =6.015 tf M1=79.889 tfm M2=79.783 tfm Omega= 0.232"Mirza":i2maghyu" said:In other words, it is possible to achieve the same result with the response spectrum method without making a structure-independent solution with fictitious inverted triangle loading? Or is it a coincidence? We want to analyze the results and check the results (M12= 25.35 Nv=16.37) under the fictitious load. ) I leave it to you.
"Mirza":21lasyqi" said:The fact that the authors of the regulation did not write the "fictitious load model" while calculating the degree of adherence stands as a shortcoming of the regulation. I leave it to the discretion of my colleagues to calculate the degree of adherence by an unwritten method in the application examples of the authors of the same regulation. [ /quote] Dear Mirza, you can get the result correctly only by isolating the tie beam shear from the structure and dissolving it with the fictitious load. This is the only way to correctly calculate the degree of attachment described in the regulation.I couldn't find your project, where did you add it as a plugin?"yusuf15hira17":21lasyqi" said:hello, I added the project data as a plugin
You cannot use A31. Pay attention to the definitions. [quote ="civilization":2mo8iqfx"]build bys=7 so A23 and A24 cannot be used automatically because I reward the build. [/quote] I don't know what causes this thought, but if you have a hollow building and BYS=>6, you will analyze and design according to A23 or A24."civilization":2mo8iqfx" said:is a building where I can use A14 as an example, I can also use A21 or A31, of course this is not an economical solution.
There are two opinions here. Those who think you wrote it like. Related link:"civilization":2mo8iqfx" said:however, even if I use A23 or A24, we automatically have to use A31 because the mdev requirement is not met.
In the old regulation, I used to put a curtain when I saw the opportunity to make it easier both in terms of the stability of the project and in terms of saving in the account. But as far as I understand, if 75% is not met even in the system consisting of simple 25 x 25 2 columns and 4 curtains (I don't understand how it is not met), it becomes impossible to put curtains except around the elevator and stairs in our 3 4 flats project. Am I right Mr. Ismail?"Ismail Hakki Besler":1l7lfi5s" said:With the regulation article 4.3.4.6, it was stipulated that the sum of the overturning moments resulting from earthquake loads on the shear walls shall not be less than 75% of the total overturning moment occurring at the base due to earthquake loads for the whole building. The tipping moment calculated for the whole structure can be calculated as equivalent or dynamically.There may be a difference of 10% between the two calculations.But the most important thing here is the contribution of the walls to the total tipping moment of the structure, especially in low-rise and flat structures, with the effect of the normal force they take as they move away from the building centre. When the calculation is made in this way, it becomes almost impossible to meet the 0.75 condition due to the axial forces of the distal walls. In order to meet this condition, it is necessary to take the shear force contribution of the beams connected to this curtain from the rigid direction. However, the regulation does not say that you can do this. It is necessary to add the Moments created by these normal forces (shear forces of the beams stuck in the wall) to the shear overturning moments. This is how ideCAD calculates the overturning moment of the tie-beam wall, which meets the degree of attachment requirement for shear walls. The regulation already calculates the overturning moment of the curtains with tie beams. However, it alone takes care of the overturning moment that occurs at the base of the walls in the walls where the beams that are not in the nature of tie beams are stuck. In Regulation 4.3.4.8 Mdev shall be calculated according to 4.5.3.7(d) or 4.5.3.8(c) for shear walls, and 4.5.4.3 for sheaths with tie beams (with spaces). If the total overturning moment M0 resulting from earthquake loads for the whole building is 4.7, 4.8.2 or 4.8.3, it will be obtained according to 4.7, 4.8.2 or 4.8.3. As such, ideCAD calculates correctly as the earthquake regulations say. In the attached project, almost all of which are curtain walls, the rollover control remains at 0.71 in the X direction. The reason is the normal forces of the curtains on the side to tip over. Earthquake regulations are incomplete as such and do not cover these situations. This control can be used as it is for curtains created close to the center in your projects. However, for these and similar projects, an additional condition may be required, as in the old 1997 regulation. In the following project, 25x25 was chosen so that the columns do not contribute to the overturning of the system. When reasonable sizes are entered, the ratio will be even smaller. When 50x50 columns are entered, Mdev/m0 decreases to 0.55.