Who will prepare the Soil Geotechnical Report?

[huseyinakkus56]

Thank you very much, Ms. Nurgul..

 

[rsb mühendislik]

After calculating the weight of the building, the g and q values in the storey parameters with the formula g+0.3q, I find the total mass (mt) by dividing the found value by 9.8067. I enter the data and the total mt in the excel sheet above, according to the entered data, the total equivalent earthquake load is 935 tf in the excel table. The equivalent earthquake load calculated by İdecad is 804 tf. Am I calculating the total mass wrong?

 

[HakanŞahin]

After calculating the building weight, g and q values in the floor parameters with the formula g+0.3q, I divide the value by 9.8067 to find the total mass (mt). According to the data entered, the total equivalent earthquake load is 935 tf in the excel table. The equivalent earthquake load calculated by İdecad is 804 tf. Am I calculating the total mass incorrectly? The formulas in the excel table are not automatic, please correct the spectrum and Ra value manually according to TBDY 2018 - SECTION 2.

 

[Muhendis30]

I understood what you mean, Mr. Ismail. My aim is to calculate that Vt value myself in line with the municipality's request. Because the municipality does not accept us to get the Vt value directly from the static report. He wants it to be calculated step by step. I also looked for a way out. but it doesn't seem like it will be calculated by hand.

Regardless of the municipality's request, a static design engineer should check the earthquake loads with a manual calculation. Creating the shared account in excel is not a camel, they give this information at school anyway.

 

[rsb mühendislik]

Mr. Hakan, although I manually corrected the formulas in the Excel table, I cannot resolve the difference. Can you check the project and excel table I have given the link below?

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Best regards,

 

[HakanŞahin]

Hakan, I can't fix the difference even though I manually corrected the formulas in the Excel table.Can you check the project and excel table I have given the link below?

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Best regards,

Hello, 1.) Since the basement is a rigid floor, the total weight of the building excluding the basement = 10506.7 tons (You don't need to divide the value by g as you wrote in the previous message, since your working unit is ton and tf) total W=16590,162 + 5*1693,472 + 0.3*140,752+0.3*5*225,302 = 10506, 7 tons Ss =0.927 S1=0.25900 Sds=1.11240 sd1=0.38850 Rx =6.4 Ry=5.6 D=2.5 I=1 2.) 5% eccentric x direction and y direction A total of 4 modal loadings are made, 2 each.You should look for the first period values with the highest contribution factor in the compatible direction for each modal loading.These values are: +x 5% T1=0.79322 sec for Modal E1 -x 5% Modal E2 T1 = 0.79252 sec +y for 5% Modal E3 T1= 0.81459 sec -y for 5%Modal E4 T1= 0.81959 sec [ b]3.)[/b] When we calculate for 4 modal loading: Vtx = 804.06 tf for Modal E1 (1) Vtx =804.76 tf for Modal E2 (2) Vty =894.80 tf for Modal E3 (3 ) For Modal E4, Vty =889.34 tf (4) 4.) You can confirm that the equivalent earthquake values are the same for each loading when you compare them with the program: 5.) From these calculations, x and for the y direction you can consider the largest value of Vt.

 

[rsb mühendislik]

Thank you very much, Mr. Hakan.

 

[batuhann2852]

Have a nice day. Good luck with. I would be very grateful if you could help me with a few questions regarding the preparation of the geotechnical report. I couldn't write it here because there are formulas in the article, I saved it as a PDF, there is an attachment, thanks.

 

[Abdullah uzun]

Good afternoon. Good luck. I have a few questions and I would appreciate it if you could help me with the preparation of the geotechnical report. I couldn't write it here because there are formulas in the article. I saved it as a PDF and there is an attachment, thanks.

1 in the formula The first part indicates the contribution of the cohesion to the bearing capacity. If there is no cohesion, it is taken as zero. The second part indicates the contribution to the bearing capacity of the excavated soil. If the foundation is not buried, it is taken as zero. If the foundation is buried, q=gamma*Df is the unit volume weight of the soil in which the gamma is excavated. indicates the contribution of the soil at the base of the foundation Gamma is the unit volume weight of the soil at the base of the foundation.

 

[batuhann2852]

Part 1 of the formula indicates the contribution of cohesion to the bearing capacity. If there is no cohesion, it is taken as zero. Part 2 indicates the contribution of the excavated soil to the bearing capacity. If the foundation is not buried, it is taken as zero, if buried, q=gamma*Df gamma is the unit weight of the ground. Part 3 specifies the contribution of the foundation size and the bearing capacity of the soil at the foundation base. Gamma is the unit volume weight of the soil at the foundation base.

Thanks for your attention. Related to part 2. Foundation There are 2 layers in the foundation foundation Radia foundation ground layer 0.5m deep, then the second layer continues. What should I get the Gamma value in the second part. The first layer will be removed, the foundation will settle on the second layer. Since the foundation is filled by 50cm, I thought I would take Df=0.5m and get the Gamma value for the unit volume weight of the second layer. C=7.92 Internal friction angle = 23.54 2nd layer floor unit weight=20.5 B(foundation width)= 8.25 As a result of these values, I find q(transport)=844.77 Kn/m2, can you take a look. C.Nc + q.Nq+ 0.5 . B . Gamma . Ngama ( other I accepted the values 1)