Defining decks at different elevations on the same floor

I look forward to the help and advice of all my colleagues who have time and can offer advice in comments; If we list what I want to ask; 1-) If we want to create a floor section with a 35 cm level difference on the ground floor, do we need to define a reverse beam system? The entrance to the building is made at +50 elevation, but the shop section will be entered from +15. Now I need to define the height of the 1st basement as 335cm and raise the lower part to +15, or should I define 300 cm and raise the entrance part of the building? 2-) How can I design and adjust the depth caused by the level difference in the stud beams in the parts with full level difference? How do we define the stud beams at +50 and the stud beam stays at +15 (K10, K15, K18) or do we need to avoid making studs at such points? 2-) We had to solve the balconies with a hollow block system, but I am waiting for your advice on choosing the most suitable system for this, I made cantilever beam extensions on 11 floors, which are the same from 1 to 10 floors, which one do you think is more reasonable? I have added the architectural and static project, to the attention of my dear colleagues who will be interested! I wish everyone a good work, take it easy...
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Re: DEFINING DECALS WITH DIFFERENT LEVELS ON THE SAME FLOOR ! * The definition of rigid basement floor number will be -1 * If you add L columns to the areas where the k10 beam is in question, your problem will be solved. This way there will be no stubs. A stud close to the support is not a correct approach anyway. That's why you can make the L column for the S9 column. * You need to make k15-18-19 beams at least 95. But the reinforcement design of thin and high beams should not be done as we know the standard. It should be reinforced with body reinforcements. But maybe he should abandon the stub as a different solution. this is the basement floor.. That is the ceiling of the 2nd basement. In that case, low-level beams can be passed from the inner columns to the outer walls. Another solution There is 25 cm level difference. If the appearance of the beams on the ceiling below is important, 35 cm ribbed flooring can be made by descending 10 cm further. You can see the attached pictures. * I wish k17-k5-k18 were continuous properly. * Define stairs on all floors. * Solve semi-rigid diaphragm. untie the ladder with the system. * Your tape beams are meaningless. In this system, it does not contribute to the account or anything else. I guess the fact that those floors have a live load of 500 is the idea of staying on the safe side. If it is a room-living room floor with a wall on it, 350 is sufficient. * You can read what is written in this forum about the purpose of using band beams. good work.
 
Re: DEFINING DECALS WITH DIFFERENT LEVEL ON THE SAME FLOOR ! HELLO NEDİM ABİ; I made the necessary adjustments in line with your recommendations. I have a few more questions to ask; 1-) Can you inspect the stairs going down to the store warehouses? I tried to keep the floor scraps small and turn them with beams as much as I could, but is there a logic error in the staircase in the hollow part? 2-) We will make balconies as hollow blocks and can I learn your opinions about the most suitable method of rib or cassette? 3-) In the parts from the basement to the roof, I would be very pleased if there are parts that you would say could have been better, Brother, the project below works without any problems in the SEMI-RIGID DIAPHRAGM. In addition, there are 3 items at the bottom of the TDY options section in the analysis settings, will we mark all three of them, and I also mark the options in the photo in the base-ground section, if I am wrong, please tell me. Good work, Take it easy..
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Re: DEFINING DECALS WITH DIFFERENT LEVELS ON THE SAME FLOOR ! There is no problem in stair layout. As for the balcony; First of all, I don't like cantilever beams from columns. This is a raft yacht and if it gets a little longer my love will fade even more. I don't know, it's like if I'm going to do it like this, would I make the ribs work the console and the floor behind it ribs? There is a piece of beam left in the s6 column on the B1 floor, you must delete it and enter the floor again. Other than that, there is no other problem in the project.
"HakanŞahin":rghpgarq" said:
"musamusa":rghpgarq" said:
In RADIUM FOUNDATION ANALYSIS 1-do the soil safety stress control of the foundations according to the average stress option 2-make a negative ground stress control in the foundations 3-soil in the foundations 1- What is the logic of calculating according to the average stress, why do we calculate according to the average stress when the normal stress is stopped, and if we do not use this option, it is difficult to save the foundations. Whatever we do. Is this because the previous versions solve the basics very safely (versions before 6) 2-What is the purpose of doing this check? We are a 3-earthquake country, as it is known, a large area of our country is a 1st and 2nd degree earthquake zone.. In this case, why is this an option? that is, what is the rationale for not using earthquake loadings in soil safety stress control? thanks
Hello, Your 1st question: Soil data are obtained by experimental results, especially in foundation calculations, the value of the 1st degree important soil bearing coefficient can vary greatly depending on the soil type. For example, while the bearing coefficient of a soil considered to be in the "clay, semi-hard" class is in the range of Ko=1000 ~ 1500 , it is in the "clay, hard" class. The bearing coefficient of the accepted soil is in the range of K0=1500 ~ 3000 . We, on the other hand, have to accept the ground bearing coefficient (1) as a single value in projects. For example, most of us would accept the average Ko= 2000 for "clay, hard soil class". The larger the base area in the foundation system, the greater the variability of this value. Horizontal coefficients according to soil class: Clay, plastic Ko=500 ~ 1000 Clay, semi-hard Ko=1000 ~ 1500 Clay, hard Ko=1500 ~ 3000 Filled soil Ko=1000 ~ 2000 Sand, loose Ko= 1000 ~ 2000 Sand, medium compact Ko=2000 ~ 5000 Sand, firm Ko=5000 ~ 10000 Sand-gravel, firm Ko=10000 ~ 15000 Solid schist Ko> 50000 Rock Ko>200000 The second point is that the soil will give under structural loads and the shape of the reaction it is not very obvious. The ground may show different behaviors according to the loads coming from the structure and again according to the ground type. Sadık Köseoğlu, in his Fundamentals book(2), divided the deformations that may occur up to the breaking point of the ground into three. Elastic deformation, plastic deformation and compressive deformation. In elastic deformation, the ground is restored when the load is removed. In plastic deformation, it shows negligible deformation when the load is removed. Compressive deformation, on the other hand, is the deformation that occurs when water and air come out of the ground, reducing the void volume and the grains coming closer to each other. More detailed information can be viewed in the relevant book. Now we have to confirm whether the soil stress released as a result of the calculation is less than the maximum soil stress. The deformations that appear at every point of the ground at the base of the building will differ according to the effects of the building. Especially at the bottom of the wall and long columns, due to the sudden increase in moment, much larger deformations may occur in some regions compared to other regions, and due to these deformations, the soil stresses at those points will be higher than the other parts of the foundation. How accurate would it be to retrofit the entire foundation system according to the large ground stress that will arise at these points? At this point, the engineer should be able to find a suitable way out by observing the predicted behavior of the ground. Average stress should be considered as one of the options given to us in this sense. Your 2nd question: The answer to this is again in the 1st answer. Under the structural loads, we have to observe whether the vertical effects lift the foundation, especially in combinations where the earthquake loads are reversed. Although the program places negative springs in the foundation system, the engineer must decide whether to allow such a behavior of the foundation. While the structure collapses at one point, it can rise at another point. While designing the foundation, we enable the program to warn us with this option. We decide whether to make changes to the build system. Your third question: Take this as an opportunity. There is an earthquake in our country. We have to design all our structures according to earthquake conditions. Apart from this, we have to give earthquake-free diathesis as an opportunity. For example, you can do a retrofitting project and earthquake effects may not have been basically taken into account at the time. You may also want to solve it and look at the state of the system. Similarly, the program is also in use abroad. For example, in Libya, the value of A0 is taken as 0.02 and the engineer does not use this option. Good work... (1)- The method to spread the ground bearing coefficient on the ground has been added to the program in version 6.0051. (Winkler) (2)- Sadık Köseoğlu Temelller sy:21
"cassabotanic":rghpgarq" said:
These options in ideCAD are for soil safety stresses only. The reinforcement calculation is the most suitable moment for earthquake +- vertical loads. It is done in a way that takes into account the unfavorable combination. In the ground safety control, there are these options for the user to take initiative in the foundation system. I think you should not worry so much about this. Some engineers still calculate by dividing the total weight of the superstructure by the raft area, which is not very wrong. Negative stress in a raft system It takes a lot of skill to remove it. Negative displacements are calculated under all conditions. But if you don't want it to bind you while taking the report, check the option to consider negative stresses. If it is not checked, it can be overlooked.
 
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