CREATING ELEVATOR PIT IN RADIUM FLOOR

[burak77]

AS YOU DESCRIPTION ET your BEST ÇALIŞMALAR..ANLATIM, PROJECT link I gave, FLOOR AND WALL of I DO ELEVATOR PIT OLUŞTURDUM..ANCAK GEOMETRY CONTROL SETTING in the KOT, LIFT in MAT FLOOR in PIT ERROR GIVES THIS REASON FIND did not GET SEVİNİRİM..KOLAY IF YOU HELP [url = https ://hotfile.com/dl/181394129/bae99f3/Avrasya3477.ide7.html]https://hotfile.com/dl/181394129/bae99f ... .ide7.html[/url]

 

[Levent Özpak]

Hello, The base system created in the project is definitely wrong. (In this way, the effect of the columns sitting on the raft slab in the foundation design is not taken into account on the raft.) The raft slab borders should be formed with the slab edge on the raft-free raft foundation. (Continuous foundation is defined on 8 axis) In the rafter raft foundation design, all columns and walls must be connected to each other with continuous foundation beams. A raft flooring should be placed on the eyes formed in between. *Beamless raft and elevator shaft can be created as in the attached project. In the project, the raft boundaries were enlarged from the left, right and upper sides, as the ground stresses exceeded the boundaries on the upper, lower and right sides of the building. The raft thickness was 100 cm. Note: In the project, the 1st and 2nd basement floors are considered rigid. There are basement perimeter curtains on some of the relevant floors. I think it should be reconsidered whether floors can be considered rigid or not. Good work

 

[burak77]

3. SHOULD WE ENTER -3 BECAUSE THE BASEMENT FLOOR SURROUNDING IS FITTED WITH CURTAIN?? OR CAN IT BE A RIGHT APPROACH TO ACCEPT RIGID IN THE 2nd BASEMENT FLOOR (INPUT RIGID FLOOR FLOOR NO -2)? THANKS

 

[Levent Özpak]

SHOULD WE ENTER -3 BECAUSE THE 3rd BODRUM FLOOR SURROUNDING IS EQUIPPED WITH CURTAIN? OR DO WE ACCEPT RIGID AT THE 2nd BODRUM FLOOR? THANKS

I think it would be appropriate to enter the rigid basement floor number -3.

 

[meraklı]

3. SHOULD WE ENTER -3 BECAUSE THE BASEMENT FLOOR SURROUNDING IS EQUIPPED WITH CURTAIN?? OR CAN IT BE A RIGHT APPROACH TO ACCEPT RIGID IN THE 2nd BASEMENT FLOOR (INPUT RIGID FLOOR FLOOR NO -2)? THANKS

I think it would be appropriate to enter the rigid basement floor number of -3.

Is it possible to enter the rigid basement floor number of -2 for this project. Or can another user enter -2? Thanks

 

[Levent Özpak]

3. SHOULD WE ENTER -3 BECAUSE THE SURROUNDINGS OF THE BODRUM FLOOR ARE EQUIPPED WITH CURTAIN? CAN WE ALSO ACCEPT RIGID (INPUT RIGID BOOM. FLOOR NO -2) BE THE RIGHT APPROACH? THANKS

I think it would be appropriate to enter the rigid basement floor number of -3.

For this project, the rigid basement floor number would be -2 Is it possible to enter it. Or can another user enter -2? Thanks

If the floor is thought to work rigidly, -2 can also be entered. Good work

 

[meraklı]

I think you mean the situation where the 3rd basement floor is rigid while the 2nd basement floor is not rigid. That is, if the rigid curtains on the 3rd basement floor do not continue on the 2nd basement floor (or else), then we enter -3.

 

[Levent Özpak]

I think you mean the situation where the 2nd basement floor is rigid while the 3rd basement floor is rigid. That is, if the rigid curtains on the 3rd basement floor do not continue on the 2nd basement floor (or not), then we enter -3.[ /quote] TDY 2007 article 2.7.2.4 and item 2.8.3.2 the definition of rigid floor is a bit open. Regulation article "The stiffness of the basement floors is very high compared to the upper floors There is an expression such as .." in buildings where there are shear walls and the basement floors operate as rigid diaphragms in the horizontal plane. Based on this expression, there are basement perimeter curtains throughout the 3rd basement floor. Therefore, the 3rd basement floor should be considered rigid. There are rigid shears on the 1st and 2nd basement floors that are not on the upper floors. However, they do not cover the entire building. Therefore, the engineer will take the initiative whether these floors are considered rigid. When the relevant floors are considered rigid (when the rigid floor number is entered), the vibration modes on these floors will not be taken into account. .So structure 7-story bookmark It will be solved like this. If the floors are not considered rigid (if the rigid floor number is entered as -3), the building will be solved as 9 floors. Meanwhile, the horizontal force TDY acting on the floors accepted as rigid shall be calculated according to the formula specified in Article 2.7.2.4 b and Figure 2.6 . I hope that has been revealing. Good work

 

[burak77]

Thank you very much for your suggestions.