Reasons for Rebar Quantity Excess

Hello. How did you decide that the quantity is too much? Why do you build non-continuous foundations of different heights? Unver ÖZCAN
 
You're right, I noticed the basic lower elevations later, and I fixed them. In this way, there is a distribution of approximately 60 kg of iron per m2, don't you think this is too much?
 
"mehmet2015":3jb0znam" said:
You're right, I noticed the basic lower elevations later, and I fixed them. In this way, about 60 kg of iron is distributed per m2, don't you think this is too much?
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I don't have such a limit value for reinforcements. I ask again. How did you calculate 60 kg?You can solve it with another program and say if it's too much in this program.This is what I'm curious about. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
 
No, I did not make such a comparison, but I thought that the value was high on average. When I solved a 4-storey building with a total construction area of 1400 m2, when I compared the kg/m2 value, I saw that the value was high. That's why I asked.
 
"mehmet2015":6336il3y" said:
No, I did not make such a comparison, but I thought that the value was high on average. When I solved a 4-storey building with a total construction area of 1400 m2, when I compared the kg/m2 value, I saw that the value was high. That's why I asked.[ /quote] The reason why I ask these questions is to create the right perspective. Even in this structure, the Engineer can make individual foundations, continuous foundations, rafter-beamed raft foundations, pile foundations together with different modeling. It will not be wrong, but it will not be economical. To be able to say the excess of reinforcements, at least It is necessary to solve and compare with three programs.There is no excess in the percentages of reinforcements (pursanta) due to the modeling in your structure, the reinforcements are within the normal limits.
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Your one-story building is covered with curtain walls all around. If you add this to the floor area, you will see that the average is slightly lower. You can also solve the three-story structure with approximately the same foundation system. This reduces the impact of the foundation per unit area. Of course, these are the things that affect the general equipment. Although the system is not difficult at all in a single storey structure, you will have to use more reinforcement by passing many reinforcements at minimum due to cross-sections. For example, if you used 25/50 columns, maybe the system would be solved with smaller columns and you would pass the minimum reinforcement with less pieces. Even using double melt on a continuous basis are factors that affect the amount of reinforcement. Therefore, it would not be right to talk about the redundancy of reinforcement (?!) over such a project. N. YILMAZ
 
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