Quantity says too much

I

ismailkara

New Member
Hello, I placed it exactly according to the architectural project, it turns out 100 kg of iron per m3. But classically, the contractor says too much and I can't convince him. However, in order to improve myself, I wonder if available friends can review my project, are there any places I need to fix or is there anything I can do to reduce it further?
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I looked at your project. You said per m3, generally it is calculated per m2, not per m3. Evaluation is done. When I look at the floor by floor, you have a floor area of 288 m2. The total amount of reinforcement belonging to that floor is approximately 6850 kg. This shows that 6850/288=23.8 kg/m2 is also a very good value. Or if we go over the total, 288m2 x 8 floors (including the foundation) = 2300 m2 Total reinforcement is approximately 50,000 kg 50,000/2300=21.7 kg/m2 This is a good amount. I think there is a language difference between you two. In my opinion, the amounts are even small, but I think it is due to the 3rd degree earthquake zone. Note: I'm not going into the design issues. The project has union security bugs galore. I think you will go. N. YILMAZ
 
First of all, continuous foundations should be from column to column, no studs should be made. Column min. Make a width of 30 cm. In general, there are column-beam junction errors in 25-columns, correct them. On the 5th floor ceiling, the load of non-walls can be reduced. Try to connect with beams in 3 directions and if you reduce the studs, your system will be more comfortable. Uncheck use ql2/12 as opening moment and changes can be made by using amps. Your size appears to be 61 tons. Your area is 285m2*7floors+38m2 engine room=2033 m2 61000/2033=30 kg/m2. This is within normal limits with changes in the system The team will change. Good work.
 
"NYILMAZ":fowctwkn" said:
I looked at your project. You said per m3, in general, the calculation is made per m2, not per m3. Evaluation is made. When I look at the floor basis, you have a floor area of 288 m2. The total amount of reinforcement for that floor is also approx. 6850 kg This shows that 6850/288=23.8 kg/m2 is a very good value, or if we go over the total, 288m2 x 8 floors (including the foundation) = 2300 m2 Total reinforcement is approximately 50,000 kg 50,000/2300=21.7 kg/ m2. This amount is also a good amount. I think there is a language difference between you. In my opinion, the amounts are even small, but I think it is due to the 3rd degree earthquake zone. Note: I am not going into the design issues. There are a lot of joint safety mistakes in the project. I think you will fix it. N. YILMAZ
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Thank you for your interest. I'm sorry I took your time. These contractors are putting us in a more difficult situation day by day. I heard something from someone saying that 40 tons would be lost, and he keeps repeating it. Although he is steep. Whether we try to stop or not, most of the people doing business in the market have the same problems.
 
"MrtGrsl":3u4rm08b" said:
First of all, continuous foundations should be from column to column, no studs should be made. Column minimum width is 30 cm, there are already column-beam junction errors in 25-column columns, correct it Try to connect the columns with beams in min. 3 directions and if you reduce the studs, it will be even more comfortable. 2033 m2 turns out to be 61000/2033=30 kg/m2. This will be within normal limits with some changes in the system.Good work.
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Thank you, thank you very much.
 
"NYILMAZ":wxk06z3e" said:
I looked at your project. You said per m3, in general, the calculation is made per m2, not per m3. Evaluation is made. When I look at the floor basis, you have a floor area of 288 m2. The total amount of reinforcement for that floor is also approx. 6850 kg This shows that 6850/288=23.8 kg/m2 is a very good value, or if we go over the total, 288m2 x 8 floors (including the foundation) = 2300 m2 Total reinforcement is approximately 50,000 kg 50,000/2300=21.7 kg/ m2. This amount is also a good amount. I think there is a language difference between you. In my opinion, the amounts are even small, but I think it is due to the 3rd degree earthquake zone. Note: I am not going into the design issues. There are a lot of joint safety mistakes in the project. I think you will fix it. N. YILMAZ
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Hello, Mr. Yılmaz, in my project, the 1290 m2 basement floor was rigid at first 50 tons, then they wanted me to drop it, but I was able to reduce it to 44 tons, but they always say that they built 30 tons of other structures on this m2. I say there will be a change in shape, but it did not. According to the current situation, is 34.1 kg\32 per m2 enough or can it be reduced further?
 
I keep the reinforcement statistics per m2 of all the projects I have drawn so far. 34 kg per m2 is normal. There is nothing exaggerated. It turns out to be 34-36 kg on average in my projects. Between 29-34kg if the structure is large. Of course, it varies according to the design, the number of floors, etc.
 
I think you shouldn't get too hung up on the footage. The important thing is to make the right design. If you pay attention to symmetry, keeping the center of mass/rigidity close, using the curtains in the right places, etc., the rest doesn't matter. What the program gives is the actual/required quantity. Contractors do not look at the issue the same as we do. They think that the project with less iron is better, and its engineer maybe better. The three cents we have already received in the market, the projects we are responsible for, at least have peace of mind. After I do what I have to do, I increase the stirrups in some elements. Let the fish not know, let Halik know.
 
You are so right, but unfortunately the contractors do not agree with us. That's why I'm always in arguments with them, trying to persuade or something.
 
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