Process steps that remove beam reinforcement area

Re: beam reinforcement area
"yunussacikk":3c4wi89p" said:
hello, can I see the step that subtracts the reinforcement face from the moment I marked in red.
Intermediate processing steps are not reported in the program for reinforced concrete section calculations. .The section calculation with the table under the effect of bending moment in the beam span is made according to the bearing capacity. You can use any reinforced concrete book for the section calculations. The sample calculation according to the beam you added is below. It is shown how to find the 3.18 cm2 reinforcement area according to the 2.946 tfm moment. Basic Principles Calculation of Bearing Capacity - Calculation of the bearing capacity of the plate section under the effect of bending moment[/b] Beam dimensions: Concrete cover=4.5 cm bw=25 cm H=50 cm d=50-4.5 = 45.5 cm Table width b= 61.1 cm Design moment Md= 2.946 tfm = 294.6 tfcm Material values: C30, S420 Fcd= 2039.432 tf/m2 = 0.204 tf/cm2 Fyd= 37241.81 tf/m2 = 3.724 tf/cm2 fctd 130.322 tf/m2 = 0.013 tf/cm2 Tabled incision t reinforcement calculation: KL=24.7 cm2/ton (for S420 and C30 from the table on page 261) K=b*d*d/Md K=61.1*45.5*45.5/294.6 K=429.36.2 cm2/ton K>KL single reinforced section (K'Fcd) = (b*d*d/Md)*fcd (K'Fcd)= 61.1*45.5*45.5*0.204/294.6= 87.59 b/bw=61.1/25=2.44 t /d=12/45.5=0.263 With interpolation from the table on page 618 J=0.982 AsAccount=Md/(fyd*j*d) Ashesap =294.6/(3.724*0.982*45.5) Ashesap=1.77 cm2 romin = 0.8 fctd/fyd = 0.8 * 130.322/37241.81 = 0.0029 (TDY 2007 Article 3.4.2.1) Asmin = 0.0029 * 25*45.5 = 3.18 cm2 Asmin is > Ashesap, so As=3.18 cm2 is used.
 
Back
Top