PARKING STATIC PROJECT HELP

[muraterb]

I AM WORKING AS A CONTROL ENGINEER. ALSO, I'M A LICENSED USER, I CANNOT GET A RESULT EVEN IF I OPENED A FEW TOPICS. THE PARKING PROJECT IN THE PICTURE HAS BEEN TENDERED AND IT WILL BE STARTED. I ENTERED AGAIN TO CHECK THE VALUES IN THE TENDERED PROJECT AND I WANTED TO CHECK IT. Since the project will be built next to the road, it is necessary to think that LOADED VEHICLES WILL PASS OVER. IN THE PROJECT, THE MOVING LOAD IS CALCULATED BY TAKING 2 T/M2. IS THIS LOAD SUITABLE AS A PLACE FOR LOADED VEHICLES? IF IT IS NOT SUITABLE, HOW DID THE LOAD NEED TO BE DONE?

 

[2m proje]

Hello there; From the picture you added, it looks like your tiles are about 5mX5m. If you take the live load of 2t/m², you define a live load of 50 tons for a slab, and if we consider that the dimensions of an aftermarket of this weight are too large to fit on a 5x5m slab, the load you have defined is too much. (Only two cars will fit on 5x5m flooring and the total weight of these vehicles will be around 5tons, 50 tons is 10 times this weight) In my opinion, 0.5 - 0.75 t/m² load will be more than enough. Best regards.

 

[muraterb]

I think that the axle load should be 20 tons in large vehicles such as trucks. However, since the axle area is larger than the plate system, if the safety factor is taken as 2 for the plate of 6mx5m; 2x20/30 = min 1.5 t/m2. It was said that the train load would not be very effective in small span plate systems. Also, it is a pity that the idestatic managers were not helpful in this matter and that I received the above answer from other static drawing program managers.

 

[Levent Özpak]

I think that the axle load should be 20 tons for large vehicles such as trucks. However, since the axle area is larger than the plate system, if the safety factor is taken as 2 for a 6mx5m plate, it becomes 2x20/30 = min 1.5 t/m2.Small It was said that the train load would not be very effective in aperture plate systems. Also, it is a pity that idestatic managers did not help and I received the above answer from other static drawing program managers.

Hello, İde YAPI is a software developer company and professionally =5]project does not provide consultancy services[/size].2m project responding to your question uses idecad software and solves projects professionally.In addition, Hakan Şahin responded to the message you wrote to the forum on 18.04.2012

Hi, It is not appropriate as an engineering approach to try to solve the project in this way... Solve your project with the consultancy of a competent person Good work.

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Good work

 

[siromar]

I think that the axle load should be 20 tons for large vehicles such as trucks. However, since the axle area is larger than the plate system, if the safety factor is taken as 2 for a 6mx5m plate, it becomes 2x20/30 = min 1.5 t/m2.Small It was said that the train load would not be very effective in aperture plate systems. Also, it is a pity that the idestatic managers did not help in this matter and I got the above answer from other static drawing program managers.

I don't understand why you got the safety factor of 2 anyway, that load will be expanded by 1.6 and you should multiply it by 2. It is not necessary- it is quite enough to take the live load of 0.75t/m2. I already saw that your project seems to have been drawn to prevent the maneuvering of the vehicles in the dimensions you mentioned. If you take it as advice, you should take the live load of the beam exactly as the live load on the floor. nor live load is a common mistake. good work

 

[muraterb]

I don't understand why you took the safety factor of 2 anyway, that load will be expanded by 1.6 and you don't need to multiply it by 2 - it's more than enough to get the live load of 0.75t/m2. I already saw that your project was drawn to prevent the maneuvering of the vehicles of the dimensions you mentioned. If you take the beam's live load as the advice, you need to take the live load of the beam exactly as the live load on the floor, it is a common mistake to say that there is no wall and neither wall nor live load is applied to the beam when there is no wall on it. good work

Thanks for your reply. However, this is a single-storey 5m high parking lot. In other words, you can think of it as a bridge where loaded trucks and trucks will pass and park at +5.00 level.

 

[saridurmus]

What your 2m project friend said is true. the load is different. it is unthinkable here, if you are afraid of it, make the first entrance and exit beams of the car park a little larger, increase the body reinforcement. When asking the question, remember that the people in front of you are human.