Load Transfer

A

Angel

New Member
Hello, We have been examining the demo of the latest version of your program for a while. The developments have been good as far as we can see. We congratulate you. We ask for your help in one issue. If we want to control the load transfer between elements in a system we are solving, is there a "short" way to do this? For example, for each floor; Total Load1=Slabs (self-weight and loads on it)+Beams (self-weight and loads)+Columns/Walls (self-weight) Total Load2=Beams (self-weight, loads, and transferred slab loads)+C-Columns/S-walls (self-weight) ) How can we "briefly" check something like Total Load3=Columns/Shears axial loads (self weight+Beams (self weight, loads on them and transferred slab loads))? Thanks for your interest, Civil Eng. Engin YÜCE
 
Hello Mr. Engin, After analyzing your project, you can examine the items you want to control on an element basis by switching to 3D frame mode on the perspective screen. If we write step by step, 1-We analyze our project. 2-Using the right-click menu on the perspective screen, we switch to 3D Frame mode. 3- In the lower right corner of the perspective screen, there is the combination we are examining. From here we can switch to the combinations we want. When we switch to 4-3D Frame mode, the Results display dialog opens, from where we can select the state we want to examine. STRUCTURE: We can examine the system consisting of rods and shells that we have created. DOWNLOADS: We can examine the loads created automatically and by the user in the system. While in the LOADS State you can inspect Element Self loads, Beam Wall loads and loads from Slabs. DEFORMATION: You can examine and animate the deformations of the Bar and Shell elements under the desired loading. FRAME RESULTS: You can examine the axial force, shear force and moments in the desired combination in beams and columns. In addition, there are options that we can examine the shell results of flooring and raft flooring. We make these inspections on an element basis, otherwise, if you switch to the Floor parameters dialog from the Analysis Menu. You can see the total G and Q loads of each Floor separately. No distinction is made such as total slab/beam/column. Good work.
 
Mr. Engin, welcome to our forum. You can easily control the load transfer between the elements by going from the axial loads as you wrote in Total Load3: If we talk about a sample system with 4 columns; Columns 40*40 cm, distance between axles 4 meters, wall load 0.325 t/m, floor height, 3.5, floor covering weight=0.15 t/m2, live load=0.2 t/m2 (You can open the attached sample project) After analysis, reinforced concrete Let's look at the end forces in the /Column/Forces Reinforcement Areas tab. Here we need to take the Ni values given under the G loading. Total Load3=Sum of axial loads of Columns/Walls Total Load3 (for G) = 4*Ni = 4* 5.074 = 20.29 tons (It is also the total fixed G load value calculated from the system loads and given on the floor basis in the floor parameters. ) Total Load3 (for Q) = 4*Ni = 4* 0.70 = 2.80 tons (Also, it is the total moving Q load value calculated from the system loads and given on the floor in the floor parameters. ) You can examine these values by clicking on the analysis floor parameters . If we provide G and Q loads manually; For load G; Slabs (self weight and loads on it)= 0.45*14.04(floor area)= 6.318 tons Beams (self weight and loads on it)= 0.25*0.5*3.6*2.5*4 + 0.325*3.6*4 = 9.18 tons Columns (self weight) = 4* 0.4* 0.4* 3* 2.5 = 4.8 tons Total = 20.29 tons for load Q; Slabs (its own weight and loads on it)= 0.200*14.04(floor area)= 2.80 tons Finally: (Beam own weight + slab loads on it)= Loads on beams, finite element in load analysis section of beam report are transmitted and displayed together with the actual load figures. Slabs (own weight and loads on it)= These values appear in the slab report as total values. (0.45 t/m2 for this example) Columns/Blinds (self-weight)= Column/wall self-weights are automatically included in the axial load as a result of the analysis. Take it easy, good work...
 
Dear Mr. Yasin and Mr. Hakan, Thank you for your quick information. We looked into the matter as you stated. It's fine, but we made a change to the example you posted. We entered the K03 elevation information of one of the beams as -150 and lowered it below the floor plane. When we enter the Report/Beam menu after making Analysis+Reinforced Concrete, it is seen that the K03 beam is still loaded from the slab on the Beam Loads page. They receive the same amount of floor loads on all four beams. However, the K03 beam does not touch the floor. In addition, when the slab finite element mesh results are examined, it is seen that there is no deterioration in the symmetry of the stresses. We are not experienced users of the program. We obviously have a definition error. What should be done in such a system? Wishing you good work, Civil Eng. Engin YÜCE
 
Mr. Engin, in order to model this system correctly, you must first enter your slab with one side empty (with the slab edge) and describe its connection in this way. Then you have to enter your beam at -150 level by giving its elevation from the beam settings and turning off the "divide by intersections" button in the toolbar (so that it does not interact with other elements). A system and screenshot entered in this way is attached.
 
Hello again, Click the geometry control button on the toolbar on the left and click OK to check the data. The program will give you an error message about the floor level. When we lower the level of the beams in this way, we also make the slab connections incorrectly, and we find that error with the geometry control. Take it easy, good work...
 
Dear Angel, I think you want the program to prepare a report that will allow you to easily check the calculations it has made for you, in accordance with the manual calculation technique. If so, could you elaborate a little more for a better understanding of the subject? I and other participants can also contribute if necessary and help the development of the subject. Floor total G = Floor self + cladding + Beam self + column self + wall weight + extra loads Floor total Q = Floor + beams + extra loads 1) Floor total column G axial forces == Floor total G 2) Floor total column Q axial forces == Floor total Q
 
From the analysis-floor parameters section, the total G and total Q values of each storey can be seen.
 
Dear Authorities and Users, Thank you very much for your interest and concern. The issue has become clearer for us. Considering the hours in which the replies were sent, thank you very much indeed. Mr. Cassabotanic, The subject we want to tell is actually as you guessed. A simple control report can be used to see the load losses that may occur during the modeling of the system (modeling error or program-based problems caused by a very, very complex system). A simple way for the user to do this, even if it's not a report. I think it's worth mentioning about this issue. If we consider that F=mxa in its simplest form. Even if "a" (acceleration) is true, "m" (mass) must also be true. It's probably getting it right maybe but it would be good to be able to see that. Wishing you good work, Civil Eng. Engin YÜCE
 
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