How do I reduce continuous base sizes

Re: continuous foundation Hello --Fix the errors in the geometry controls, --You can reduce the live loads on the attic floor and remove the wall loads, --The upper rigid floor number will be -2, --Make a semi-rigid diaphragm solution with the ladder , -- Subtract the wall width on the rib beams and give it as live load, (0.70-0.20 (wall)=0.50*0.200=0.1 t/m2) --Foot height 70 cm would be more appropriate. Unver ÖZCAN
 
hello sir, I reduced the live loads under the roof from 0.35 to 0.2, I made the upper rigid floor number-2, I made a semi-rigid solution, I made the trmrl height 70 cm, but there is an interesting situation, I am doing geometry control, I have mistakes, the 4th floor says that the beam height is less than three floors of the deck no way, I dropped the hood from 22 cm to 19 cm. It still gives the same error, it says 60 cm in ha beam plus column plus deck, that is, column 70 deck height 32 must be from beam width....
 
Hello. If the subject is the 4th FLOOR and you are going to make it ribbed; Here, the floor thickness seems to be 22 cm. Take the thickness of 7 cm like the floors below and make ribs. (22 cm is too much) If you are going to slab without beams, define the outer borders with the tile edge command and define the slab inside. (in both cases, raise the elevator shaft.) Ünver ÖZCAN
 
Back
Top