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Turkish have a nice day. In the project in the picture, the floor is 3.15 m and the mezzanine floor is 3 m high. The flooring forming the mezzanine remains very small compared to the building session. I want to ask, should I enter these two floors separately or should I define a floor of 6.15 m height and create two diaphragms by giving a negative level to the beams and floors?
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Floor identification
- Thread starter gunner
- Start date
Levent Özpak
New Member
Hello, it would be appropriate to define the floors at +3.15 (suspended) and +6.15 (ground) elevations on different floors. Good work
first of all, thank you for your quick response. This is the floor view of the slab on the ground floor. As seen on this floor, none of the columns except the 8 columns form a frame with the beam or the floor. If we solve the column, which will actually reach 6.15 meters, as if it were two overlapping columns of 3 meters each, we would not have made a mistake in the buckling calculation of that column. are we"Levent Özpak":1rb8cb7b" said:Hi, it would be appropriate to define the floors at +3.15 (suspended) and +6.15 (ground) levels on different floors. Good work
Levent Özpak
New Member
Hello, Many columns on the ground floor are not connected to beams. Columns that are not connected to beams are not included in the effective shear area of the floor in B1 irregularity control. If you want to include them, you can add them to the +Awx and +Awy columns in the Analysis / Floor Parameters / Irregularities tab. Also, the effective shearing area of the wall in the mezzanine floor seems quite less compared to the 1st floor . Good work"gunner":2wdc11fv" said:hello, when I enter the floors as you say, I am constantly encountering b1 irregularity. I could not go above 0.60 somehow. The project is attached. I would be very grateful if you could help.