Hello; There are a few issues I wonder about Idecad Static; In Finite Element analysis, does the [K] [M] and [C] matrices convert to the "banded" state after this solution is created? As it is known, there are plenty of zeros in these matrices and these zeros are scattered in the matrix. By reordering these matrices, these clutter can be reduced and solution time can be reduced. Also, is the "substructing" method used for building-ground interactive solution in finite element solution? The reason for asking these questions is that I am solving a 12-storey pile-based building model and the analysis time takes 15 minutes. I am attaching the analysis status for those who are interested. If the issues I mentioned above are already implemented in the program, there is nothing that can be done anyway. Finally, while modeling the structure, if idecad creates system matrices in a static background, wouldn't this shorten the solution time? Considering the project I'm working on right now. After the initial analysis, the system generates the [K ] [M] and [C] matrices once and updates only the necessary elements of these matrices for further changes. Or, those who use the Substructuring method create the matrices of each floor during modeling without analysis. Substructuring method is a very common method used in finite element analysis. Thanks to this method, finite element analysis time can be reduced. If I explain this very briefly. For a 10-storey building, there are 500 degrees of freedom on each floor and there will be a total of 5000 degrees of freedom. So [K] [M] [C] matrices would be 5000x5000 matrices. But if substructuring is used, the matrices of the 10 layers will be formed in terms of 9-fold degrees of freedom. The matrices of the 9 layers will be formed in terms of 8-fold degrees of freedom. . . The matrices of 2 layers are formed in terms of 1 layer degrees of freedom. The matrices of the 1st floor are formed in terms of the degrees of freedom of the ground floor. As a result, the system to be solved is reduced from 5000x5000 to 500x500. As a result of the analysis, the solution is applied from the bottom up by applying the opposite of what I wrote above. Are these methods used for idecad finite element analysis? Best regards 0:00 Starting the analysis. It uses 2 core processors. 0:00 Generating geometry. 0:00 Rigid diaphragms are detected. 0:01 Calculating floor weights and centroids. 0:02 Defining cantilever beams. 0:02 Building system is being created. 2:06 Regulation checks are in progress. 2:07 Strong floor control in progress 2:12 Calculating floor loads on elements. Calculating "TOWER". Calculating "FLOOR 12". Calculating "11th FLOOR". Calculating "FLOOR 10". Calculating "FLOOR 9". Calculating "FLOOR 8". Calculating the "7th FLOOR". Calculating "FLOOR 6". Calculating "FLOOR 5". Calculating "FLOOR 4". Calculating the "3rd FLOOR". Calculating "FLOOR 2". Calculating "FLOOR 1". Calculating "GROUND FLOOR". 2:44 Loading build. 2:44 Calculating element loads. 4:12 Checking for B3 irregularity. 4:12 Analysis is in progress. 4:20 Performing a modal analysis: "Modal". Number of iterations: 2 Relative change of frequency: 8.18849e-005. 18 mods wanted, 18 mods found. Mode 0: f=0.83171 T=1.20234 Mode 1: f=0.88189 T=1.13393 Mode 2: f=1.12154 T=0.89163 Mode 3: f=2.90250 T=0.34453 Mode 4: f=3.06229 T=0.32655 Mode 5: f= 4.29451 T=0.23286 Mode 6: f=5.54472 T=0.18035 Mode 7: f=6.29989 T=0.15873 Mode 8: f=8.67009 T=0.11534 Mode 9: f=9.17459 T=0.10900 Mode 10: f=10.43673 T=0.09582 Mode 11: f=12.18565 T=0.08206 Mode 12: f=13.85144 T=0.07219 Mode 13: f=14.97253 T=0.06679 Mode 14: f=15.66746 T=0.06383 Mode 15: f=16.29644 T=0.06136 Mode 16: f=19.56570 T=0.05111 Mode 17: f=19.82317 T=0.05045 6:10 Floor loads are calculated. 6:10 Calculating TOWER forces. 6:10 12. Calculating FLOOR forces. 6:10 11. Calculating FLOOR forces. 6:10 10. Calculating FLOOR forces. 6:10 Calculating 9. FLOOR forces. 6:10 8. Calculating FLOOR forces. 6:10 Calculating 7. FLOOR forces. 6:10 Calculating 6th FLOOR forces. 6:10 Calculating the 5th FLOOR forces. 6:10 Calculating 4th FLOOR forces. 6:10 Calculating 3rd FLOOR forces. 6:10 Calculating 2nd FLOOR forces. 6:10 Calculating 1st FLOOR forces. 6:10 Calculating FLOOR FLOOR forces. 6:10 Calculated loads are being applied to the system. 7:49 Doing linear static analysis. Installing "EX" is in progress. Installing "EY" is in progress. Installing "EX1" is in progress. Installing "EX2" is in progress. Installing "EY1" is in progress. Installing "EY2" is in progress. Installing "G" is in progress. Loading "Q" is in progress. 12:07 Calculating centers of mass and stiffness. 12:12 Reinforced concrete calculation is done. 12:16 Reinforced concrete is being made. 12:29 Structural irregularities are being examined. 12:29 TDY item 3.3.5 (strong colon control) is done. 12:30 TDY article 3.6.6 - The design effects of the curtains are calculated. 12:30 Design results are available. 12:30 TDY item 2.7.5 - Internal forces in the principal axis direction of the element are increased. 12:30 TDY item 3.3.6.2 - Internal forces are multiplied by 1/alpha. 12:30 TDY item 2.8.5 - The internal forces of the elements are increased. 12:30 TDY item 2.3.2.4 - With B3 irregularity, the internal forces of the element are increased. 12:30 TS500 6.3.8 - Redistribution clause is applied. 12:31 TS500 Item 6.3.10 (Minimum eccentric control) is done. 12:31 TS500 article 7.6.2.5 - Column sprain (slenderness) calculation is made. 12:31 System recalculation with augmented results. 12:45 TDY article 3.4.1.2 - Normal force control is performed on beams. 12:45 TDY article 3.4.3.1 (minimum a and b checks of beam reinforcements in columns) is done. 12:46 TS500 item 11.2 - Floor dimension checks are carried out. 12:48 TS500 item 13.2 - Deflection control is performed on the beams. 12:48 Static analysis is performed with constant loads for deflection control. 12:48 Fundamental analysis is being done. 13:13 Static analysis is performed with live loads for deflection control. 13:33 TS500 article 13.3.2 - Checking for cracks in beams is done. 13:33 Fundamental analysis finished. 13:33 Slab analysis. 13:33 "TOWER" flooring analysis is being done. 13:34 "FLOOR 6" flooring analysis is in progress. 13:34 TS500 item 13.2 (Floor deflection control) is being done: TOWER 13:35 "12th FLOOR" floor analysis is being done. 13:48 TS500 item 13.2 (Floor deflection control) is being done: 12th FLOOR 13:48 "11th FLOOR" floor analysis is being done. 13:49 TS500 item 13.2 (Floor deflection control) is being done: 6th FLOOR 13:49 "5th FLOOR" floor analysis is being done. 13:59 TS500 item 13.2 (Floor deflection control) is being done: 11. FLOOR 13:59 "10th FLOOR" flooring analysis is being done. 14:00 TS500 item 13.2 (Floor deflection control) is being done: 5th FLOOR 14:01 "4th FLOOR" floor analysis is being done. 14:09 TS500 item 13.2 (Floor deflection control) is being done: 10th FLOOR 14:09 "9th FLOOR" flooring analysis is being done. 14:13 TS500 item 13.2 (Floor deflection control) is being done: 4th FLOOR 14:13 "3rd FLOOR" floor analysis is being done. 14:23 TS500 item 13.2 (Floor deflection control) is being done: 3rd FLOOR 14:23 "2nd FLOOR" flooring analysis is being done. 14:24 TS500 item 13.2 (Floor deflection control) is being done: 9th FLOOR 14:24 "8th FLOOR" floor analysis is being done. 14:33 TS500 item 13.2 (Floor deflection control) is being done: 2nd FLOOR 14:33 "1st FLOOR" floor analysis is being done. 14:35 TS500 item 13.2 (Floor deflection control) is being done: 8th FLOOR 14:35 "7th FLOOR" floor analysis is being done. 14:49 TS500 item 13.2 (Floor deflection control) is being done: 1. FLOOR 14:49 "GROUND FLOOR" slab analysis is being done. 14:52 TS500 item 13.2 (Floor deflection control) is carried out: 7. FLOOR 14:59 TS500 item 13.2 (Floor deflection control) is carried out: GROUND FLOOR 14:59 TS500 item 8.3.1 - Stapling controls are carried out. 15:02 Analysis completed.