Defining a point and uniformly distributed load on the beam

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201968

New Member
I want to add a point and evenly distributed load on the K01 beam. I define the distance to the point load value part as 1.65m and when I define the uniformly distributed load as 1.60 m to the right end and 3 m to the left end, the point load average is required, but it does not average. You can examine it over the K01 beam in the attached project.
 
Re: VERY EMERGENCY HELP (EXTERNAL LOAD DEFINITION) Hello. Since the beam element length is taken from the middle axis of the beams, define the distances by considering the length of K01 Beam as 430cm. For a uniformly distributed load, if you enter the left distance as 1.6m and the right distance as 2.6m, the load will be centered according to the single load defined in 1.65. If you want to average the point load, you need to get the distance 2.15
 
Mr. Yasin, 1.65 m was the distance from the right end of the beam, then should I take the distance of the point load according to the middle of the beam again (the distance of the right end of the point load is 1.65m, in this logic, if the program is based on the middle of the beam, I should enter 1.45) is it correct?
 
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