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Curtain cutting problem...
- Thread starter celikbey
- Start date
Re: Curtain cutting problem... Emergency help... Hello; It will be enough to add a raft foundation and make a Structure-Foundation Interactive solution. This kind; In systems where curtains are used very little, it is normal for shear damage to occur, especially on curtains that are between two curtains as in your project and whose displacements are limited by the curtains at the beginning. The Structure-Basic interactive solution will cause the cross-section effects on the superstructure to be partially reduced (as a more sensitive and realistic solution is made due to collapses and rotations on the ground), which will provide the system to relax. Ünver's suggestion is a suitable solution with a similar logic. Best regards...
Different problems I have one more question. My slab in the tower only recovers as a slab when it reaches 17 cm thick. However, when I calculate according to the equation in TS500 11.4.2, it turns out to be 12.4 cm. So if I do 13 it will work but it doesn't work? Also, I don't have rib and tape results in the reinforced concrete tab. The system doesn't seem to work. I will be glad if you answer. Have a nice day.
Levent Özpak
New Member
Re: Different problems
*The calculation beams (typical beam) of the ribbed floor on the tower floor were not defined."celikbey":y7vqg1e0" said:I have one more question. My slab in the tower only recovers when it reaches 17 cm thickness. However, when I calculate according to the equation in TS500 11.4.2, it is 12.4 cm. It turns out. So if I do 13, it will work, but it doesn't work. And I don't have rib and tape results in the reinforced concrete tab. It seems like the system doesn't solve it. I would appreciate it if you could answer. Good day.
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*Manual thickness control in case of slab on tower floor; Good workRe: Different problems
Hello Mr. Levent. I missed the typical beam issue in cassette and toothed floors. As for the other issue; The AlphaS coefficient doesn't come out to 0, right? Since the continuous edge and the total edge length are equal, (Total continuous edge length)/(Total edge length)=1. In this case, since it is (1-As/4) in the equation, it becomes 1-(1/4), ie 0.75. It is already 16.45 x 0.75 = 12.33. On the other hand, isn't a 5.60 x 5.90 m slab a normal room? Let it go up to 15 cm. You do not think so?"Levent Özpak":3n1zr8j7" said:*The calculation beams (typical beam) of the ribbed flooring on the tower floor are not defined."celikbey":3n1zr8j7" said:I have one more question. My slab in the tower only recovers as a slab when it reaches 17 cm thick. However, when I calculate according to the equation in TS500 11.4.2, it turns out to be 12.4 cm. So if I do 13 it will work but it doesn't work? Also, I don't have rib and tape results in the reinforced concrete tab. The system doesn't seem to work. I will be glad if you answer. Good day.You do not have permission to view link Log in or register now.*Manual thickness control in case of slab on tower floor ; Good work
Re: Curtain cutting problem... Urgent help...
Thank you, Unver, I will try"unver":28r3rcuk" said:Hi - How did you find the -13 cm? -There is a problem with your settings. Mine gives calculation and drawing results .Check your settings.--Or download and check this setting.Unver ÖZCAN
Levent Özpak
New Member
Re: Different problems
The floor on the tower floor is a single floor. There is no other flooring around it. Hence the continuous edge length is zero.Hello Mr. Levent. ... As for the other issue; The AlphaS coefficient doesn't come out to 0, right? Since the continuous edge and the total edge length are equal, (Total continuous edge length)/(Total edge length)=1. In this case, since it is (1-As/4) in the equation, it becomes 1-(1/4), ie 0.75. It is already 16.45 x 0.75 = 12.33. On the other hand, isn't a 5.60 x 5.90 m slab a normal room? Let it go up to 15 cm. Don't you think so?
Re: Different problems
Thanks."Levent Özpak":u7k3msd3" said:The slab on the tower floor is a single slab. There is no other slab around it. Therefore, the continuous side length is zero.Hello Mr. Levent ... As for the other issue, the AlphaS coefficient does not come out as 0 there? Since the continuous edge and the total edge length are equal (Total continuous side length)/(Total side length) = 1. In this case, since (1-Ace/4) in the equation, 1-(1/4) becomes 0.75. It is already 16.45 x 0.75 = 12.33. On the other hand, 5.60 x Isn't a 5.90 m long slab a normal room? It should be 15 cm maximum. Don't you think so?