Creating a spiral staircase without a landing

"Levent Özpak":2ryjxfdj" said:
"sevdae":2ryjxfdj" said:
Good work guys, I couldn't draw the spiral staircase without a landing in ideCAD, which I added a picture of, can you help?
Hello, You can create the staircase as attached. You can get information about the creation of stairs and the determination of support conditions from the links below. -Creating the ladder
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-Defining the ladder support conditions
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Good work
Hello, Brother, are you drawing the ladder in 3 parts? Also, are you drawing from architecture?
 
The staircase can be created by taking the base from the architecture. The attached staircase was created based on the pictures added by Mr. "Sevdae". Good work
 
Thank you very much Mr. Levent, I applied what you said.. Should I analyze the staircase together with the building or independently of the building? I also had a problem while throwing the account axles because I had a problem with the reinforcements.
 
I suggest that the ladder be solved together with the structure. If you are going to solve it independently of the structure, you can enter the ladder loads as an additional load on the relevant elements. Dissolving the ladder with or without the structure has no effect on the definition of the ladder reinforcement axes. Reinforcement drawings of straight-armed ladders are made automatically in the program. Reinforcement drawings must be edited for spiral arm ladders. Good work
 
I tried to make a solution with the structure, but the reinforcement diameters are large. Like 18-20. Why could it be? Could it be one of the supporting conditions? Or could it be caused by account axles? In the video you linked, the account axis is thrown along the direction of the staircase, but while I am throwing the account axis, it cuts the account axis at 6 steps?
 
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