Calculation of Pile Spring Constants

[MaFiAMaX]

Hello, I made a simple example to understand the modeling of pile spring constants in ideCAD. However, I couldn't figure out how to calculate the calculated horizontal and vertical spring constants. You can see the example in the attached image. I would like you to indicate how you calculated the horizontal and vertical spring constants. Good work.

 

[HakanŞahin]

Given floor height = 5.70 m There are 12 points. hi(unit height) =5.7/12 = 0.475 for example horizontal for 8th point: zi=0.475*8= 3.8 meters ki=Kazikcapi*zi*hi*Kyatak ki = 1.0 * 3.8 * 0.475 * 3000 = 5415 tf/m for vertical; Ki= LateralKAzikArea * Kvertical Ki= 1.0 * 0.475 * 2000 = 950 tf/m It is shared half as ki/2 at the 1st and last node.

 

[MaFiAMaX]

Hank, thank you for your reply. When I imported the model to SAP2000, I realized the spring coefficients and I asked this question because it was different from what I normally do manually. That is, for the 8th point horizontally: zi=3.8m, calculating the lateral bearing coefficient at that depth from the empirical formula (I think ideCAD calculates linearly by multiplying with zi in the calculation), ki=Pile lateral area * Kyatay = pi* r * 0.475 * For Kyatay Vertical: ki=lateral pile area * KVertical = 2 * pi *r * 0.475 * 2000=2983 tf/m In your calculation, the half surface area of the pile is taken as a cross section. What is the reason of this?

 

[HakanŞahin]

Hakan, Thank you for your reply. When I imported the model to SAP2000, I realized the spring coefficients and I asked this question because it was different from what I normally do manually. That is, for point 8, horizontal: zi Calculate the lateral bearing coefficient at that depth from the empirical formula given for =3.8m (I think ideCAD calculates linearly by multiplying it with zi in the calculation), ki=Pile lateral area * Kyatay = pi* r * 0.475 * Khorizontal For vertical: ki=lateral pile area * Kvertical = 2 * pi *r * 0.475 * 2000=2983 tf/m In your calculation, the semi-surface area of the pile is taken as a cross section. What is the reason for this?

Horizontally, the area is not circular anyway. In the vertical, rectangular area is used depending on the height. We'll take note of this issue for review...