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Turkish first of all, good work guys, something stuck in my mind in my project that I added below, basement floor 1 2 A 3-storey project and a symmetrical structure; but the 1st and 2nd floors are on the same 3rd floor, in addition to these floors, there are fringes. My question is why the mass stiffness centers of the 1st and 2nd floors are located in different places, and since the structure is symmetrical, they should not overlap in the middle, am I wrong, am I waiting for your support? idecad file
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about the center of mass rigidity
- Thread starter etriye
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It's not the same. Your structure is not symmetrical on both axes. It's only symmetrical with respect to the Y axis, so the y coordinates of the centers of stiffness of the two floors will not be the same."etriye":egb8dfqu" said:thanks for your attention, but my question is exactly that the 1st and 2nd floors are exactly the same, so wouldn't their center of rigidity be the same for these two floors? As you can see in the picture, there is a small boat between them. It's in the same place, but there is a slight deviation in stiffness, I'm curious about it (column beam at 2 floors) It's not the same
Under the influence of earthquake forces, the point where the resultant of the shear forces formed in the vertical carrier elements (column, beam) passes is the center of rigidity. (the earthquake force differs for each floor. For example, if there is a shear force of 10 t for the zso1 column (on the ground floor), SO1 means a shear force of 12 t on the 1st floor. may come, so the center of rigidity may change) I know that, sorry.
@matrax I think it may be like you said, although there is no serious difference, there is a difference. I will call idecad technical support and write the result here, thank you for your interest @merakli km The difference in the places of rm rather than the places of rm confused me
HakanŞahin
Administrator
"etriye":2dcnpf3h" said:@matrax may be as you said, I think there is a difference, even if there is no serious difference, I will call idecad technical support and write the result here, thank you for your attention @curious km I was confused by the difference in rm's locations rather than rm's locations[/quote ] Hello, As explained in the link given by matrax between floors, for the center of stiffness coordinate, it is necessary to find the average of the values obtained by multiplying the column shear forces from the earthquake at each floor with the column coordinate. As long as the location of the center of stiffness at each floor is not at the same coordinate Xr=Sum(ColumnVyi*xi)/Sum(ColumnVy) Yr=Sum(ColumnVxi*yi)/Sum(ColumnVx) On the floor plane, your structure is symmetrical in x direction, Not in the y direction So Km and Rm coincide in the x direction but not in the y direction Good work
"etriye":3tqas3bi" said:@matrax I think it may be as you said, although there is no serious difference, there is a difference. I will call idecad technical support and write the result here, thank you for your attention @curious km The difference in the places of the rm rather than the places of the rm confused me[/quote ] Even if the dimensions of the beams of the columns on two different floors are exactly the same, if the structure is not symmetrical in both axes, Xr and Yr will not be in the same coordinates. I will help you if you tell me where it got mixed in. In this project, since your structure is symmetrical with respect to the Y axis, the Xr's are the same on both floors. Since your structure is not symmetrical with respect to the X axis, it cannot be expected that the Yrs will be the same.
If x and y are the same, they overlap as you said, but my production differs from the floor shear forces consisting of symmetrical earthquake forces in one direction. The reason is because of the floor shear forces, as Hakan said, it is not the same in my project, there is very little difference, the reason is because the programs are different...